| 1 | /* Oki bug report [OKI004](gcc005) |
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| 2 | |
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| 3 | The following computation is no work. |
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| 4 | -1 / 1 => 1 (correct -1) |
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| 5 | -1 % 2 => 1 (correct -1) |
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| 6 | */ |
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| 7 | |
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| 8 | #include <stdio.h> |
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| 9 | |
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| 10 | main () |
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| 11 | { |
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| 12 | long l1, l2, l6; |
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| 13 | auto long l3; |
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| 14 | long oza1, oza2, oza; |
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| 15 | |
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| 16 | l1 = 1; |
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| 17 | l2 = 2; |
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| 18 | l3 = -1; |
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| 19 | l6 = 6; |
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| 20 | |
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| 21 | /*** test 1 ***/ |
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| 22 | oza = ((l3 / ((l1)--)) | (l6 <= (l3 % l2))); |
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| 23 | printf ("test 1 has a result of %d.\n", oza); |
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| 24 | if (oza != -1) |
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| 25 | fail ("divide test [OKI004]"); |
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| 26 | else |
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| 27 | pass ("divide test [OKI004]"); |
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| 28 | |
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| 29 | l1 = 1; |
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| 30 | /*** test 2 ***/ |
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| 31 | oza1 = (l3 / ((l1)--)); |
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| 32 | oza2 = (l6 <= (l3 % l2)); |
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| 33 | oza = oza1 | oza2; |
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| 34 | |
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| 35 | printf ("test 2 has a result of %d.\n", oza); |
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| 36 | if (oza != -1) |
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| 37 | fail ("modulos test [OKI004]"); |
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| 38 | else |
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| 39 | pass ("modulos test [OKI004]"); |
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| 40 | fflush (stdout); |
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| 41 | |
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| 42 | test_1(); |
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| 43 | } |
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| 44 | |
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| 45 | /* |
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| 46 | 32760 / (1) = 32760 |
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| 47 | 32760 / (-1) = 32760 -------> ERROR, same as you said. |
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| 48 | 32760 / (2) = 16380 |
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| 49 | 32760 / (-2) = -2147467268 ----> ERROR |
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| 50 | 32760 / (3) = 10920 |
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| 51 | 32760 / (-3) = -1431644845 ----> ERROR |
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| 52 | 32760 / (4) = 8190 |
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| 53 | 32760 / (-4) = -8190 |
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| 54 | */ |
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| 55 | test_1() |
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| 56 | { |
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| 57 | int value, i, j; |
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| 58 | |
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| 59 | i = 32760; |
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| 60 | j = 1; |
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| 61 | value = i / (j); |
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| 62 | printf ("%d / (%d) = %d\n", i, j, value); |
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| 63 | j = -1; |
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| 64 | value = i / (j); |
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| 65 | printf ("%d / (%d) = %d\n", i, j, value); |
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| 66 | |
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| 67 | j = 2; |
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| 68 | value = i / (j); |
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| 69 | printf ("%d / (%d) = %d\n", i, j, value); |
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| 70 | j = -2; |
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| 71 | value = i / (j); |
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| 72 | printf ("%d / (%d) = %d\n", i, j, value); |
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| 73 | |
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| 74 | j = 3; |
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| 75 | value = i / (j); |
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| 76 | printf ("%d / (%d) = %d\n", i, j, value); |
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| 77 | j = -3; |
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| 78 | value = i / (j); |
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| 79 | printf ("%d / (%d) = %d\n", i, j, value); |
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| 80 | |
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| 81 | j = 4; |
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| 82 | value = i / (j); |
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| 83 | printf ("%d / (%d) = %d\n", i, j, value); |
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| 84 | j = -4; |
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| 85 | value = i / (j); |
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| 86 | printf ("%d / (%d) = %d\n", i, j, value); |
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| 87 | } |
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| 88 | |
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