1 | #include "dietfeatures.h" |
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2 | #include <unistd.h> |
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3 | #include <md5.h> |
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4 | |
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5 | /* Initial permutation, */ |
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6 | static const char IP[] = { |
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7 | 57,49,41,33,25,17, 9, 1, |
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8 | 59,51,43,35,27,19,11, 3, |
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9 | 61,53,45,37,29,21,13, 5, |
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10 | 63,55,47,39,31,23,15, 7, |
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11 | 56,48,40,32,24,16, 8, 0, |
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12 | 58,50,42,34,26,18,10, 2, |
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13 | 60,52,44,36,28,20,12, 4, |
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14 | 62,54,46,38,30,22,14, 6 |
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15 | }; |
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16 | |
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17 | /* Final permutation, FP = IP^(-1) */ |
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18 | static const char FP[] = { |
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19 | 39, 7,47,15,55,23,63,31, |
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20 | 38, 6,46,14,54,22,62,30, |
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21 | 37, 5,45,13,53,21,61,29, |
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22 | 36, 4,44,12,52,20,60,28, |
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23 | 35, 3,43,11,51,19,59,27, |
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24 | 34, 2,42,10,50,18,58,26, |
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25 | 33, 1,41, 9,49,17,57,25, |
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26 | 32, 0,40, 8,48,16,56,24 |
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27 | }; |
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28 | |
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29 | /* Permuted-choice 1 from the key bits to yield C and D. |
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30 | * Note that bits 8,16... are left out: They are intended for a parity check. |
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31 | */ |
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32 | static const char PC1_C[] = { |
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33 | 56,48,40,32,24,16, 8, |
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34 | 0,57,49,41,33,25,17, |
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35 | 9, 1,58,50,42,34,26, |
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36 | 18,10, 2,59,51,43,35 |
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37 | }; |
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38 | |
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39 | static const char PC1_D[] = { |
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40 | 62,54,46,38,30,22,14, |
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41 | 6,61,53,45,37,29,21, |
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42 | 13, 5,60,52,44,36,28, |
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43 | 20,12, 4,27,19,11, 3 |
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44 | }; |
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45 | |
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46 | /* Sequence of shifts used for the key schedule. */ |
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47 | static const char shifts[] = { 1,1,2,2,2,2,2,2,1,2,2,2,2,2,2,1 }; |
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48 | |
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49 | /* |
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50 | * Permuted-choice 2, to pick out the bits from the CD array that generate |
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51 | * the key schedule. |
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52 | */ |
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53 | static const char PC2_C[] = { |
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54 | 13, 16, 10, 23, 0, 4, 2, 27, 14, 5, 20, 9, |
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55 | 22, 18, 11, 3, 25, 7, 15, 6, 26, 19, 12, 1 |
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56 | }; |
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57 | |
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58 | static const char PC2_D[] = { |
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59 | 12, 23, 2, 8, 18, 26, 1, 11, 22, 16, 4, 19, |
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60 | 15, 20, 10, 27, 5, 24, 17, 13, 21, 7, 0, 3 |
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61 | }; |
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62 | |
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63 | /* The C and D arrays used to calculate the key schedule. */ |
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64 | |
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65 | static char C[28]; |
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66 | static char D[28]; |
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67 | /* The key schedule. Generated from the key. */ |
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68 | static char KS[16][48]; |
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69 | |
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70 | /* The E bit-selection table. */ |
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71 | static char E[48]; |
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72 | static const char e2[] = { |
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73 | 32, 1, 2, 3, 4, 5, 4, 5, 6, 7, 8, 9, |
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74 | 8, 9, 10, 11, 12, 13, 12, 13, 14, 15, 16, 17, |
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75 | 16, 17, 18, 19, 20, 21, 20, 21, 22, 23, 24, 25, |
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76 | 24, 25, 26, 27, 28, 29, 28, 29, 30, 31, 32, 1 |
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77 | }; |
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78 | |
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79 | /* Set up the key schedule from the key. */ |
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80 | void setkey(const char *key) |
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81 | { |
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82 | register int i, j, k; |
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83 | int t; |
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84 | int s; |
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85 | |
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86 | /* First, generate C and D by permuting the key. The low order bit of each |
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87 | * 8-bit char is not used, so C and D are only 28 bits apiece. |
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88 | */ |
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89 | for(i=0; i < 28; i++) { |
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90 | C[i] = key[(int)PC1_C[i]]; |
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91 | D[i] = key[(int)PC1_D[i]]; |
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92 | } |
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93 | /* To generate Ki, rotate C and D according to schedule and pick up a |
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94 | * permutation using PC2. |
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95 | */ |
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96 | for(i=0; i < 16; i++) { |
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97 | /* rotate. */ |
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98 | s = shifts[i]; |
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99 | for(k=0; k < s; k++) { |
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100 | t = C[0]; |
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101 | for(j=0; j < 27; j++) |
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102 | C[j] = C[j+1]; |
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103 | C[27] = t; |
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104 | t = D[0]; |
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105 | for(j=0; j < 27; j++) |
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106 | D[j] = D[j+1]; |
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107 | D[27] = t; |
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108 | } |
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109 | /* get Ki. Note C and D are concatenated. */ |
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110 | for(j=0; j < 24; j++) { |
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111 | KS[i][j] = C[(int)PC2_C[j]]; |
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112 | KS[i][j+24] = D[(int)PC2_D[j]]; |
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113 | } |
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114 | } |
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115 | |
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116 | for(i=0; i < 48; i++) |
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117 | E[i] = e2[i]; |
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118 | } |
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119 | |
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120 | /* The 8 selection functions. For some reason, they give a 0-origin index, |
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121 | * unlike everything else. |
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122 | */ |
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123 | static const char S[8][64] = { |
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124 | { |
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125 | 14, 4,13, 1, 2,15,11, 8, 3,10, 6,12, 5, 9, 0, 7, |
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126 | 0,15, 7, 4,14, 2,13, 1,10, 6,12,11, 9, 5, 3, 8, |
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127 | 4, 1,14, 8,13, 6, 2,11,15,12, 9, 7, 3,10, 5, 0, |
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128 | 15,12, 8, 2, 4, 9, 1, 7, 5,11, 3,14,10, 0, 6,13 |
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129 | }, |
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130 | |
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131 | { |
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132 | 15, 1, 8,14, 6,11, 3, 4, 9, 7, 2,13,12, 0, 5,10, |
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133 | 3,13, 4, 7,15, 2, 8,14,12, 0, 1,10, 6, 9,11, 5, |
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134 | 0,14, 7,11,10, 4,13, 1, 5, 8,12, 6, 9, 3, 2,15, |
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135 | 13, 8,10, 1, 3,15, 4, 2,11, 6, 7,12, 0, 5,14, 9 |
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136 | }, |
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137 | |
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138 | { |
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139 | 10, 0, 9,14, 6, 3,15, 5, 1,13,12, 7,11, 4, 2, 8, |
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140 | 13, 7, 0, 9, 3, 4, 6,10, 2, 8, 5,14,12,11,15, 1, |
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141 | 13, 6, 4, 9, 8,15, 3, 0,11, 1, 2,12, 5,10,14, 7, |
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142 | 1,10,13, 0, 6, 9, 8, 7, 4,15,14, 3,11, 5, 2,12 |
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143 | }, |
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144 | |
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145 | { |
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146 | 7,13,14, 3, 0, 6, 9,10, 1, 2, 8, 5,11,12, 4,15, |
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147 | 13, 8,11, 5, 6,15, 0, 3, 4, 7, 2,12, 1,10,14, 9, |
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148 | 10, 6, 9, 0,12,11, 7,13,15, 1, 3,14, 5, 2, 8, 4, |
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149 | 3,15, 0, 6,10, 1,13, 8, 9, 4, 5,11,12, 7, 2,14 |
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150 | }, |
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151 | |
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152 | { |
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153 | 2,12, 4, 1, 7,10,11, 6, 8, 5, 3,15,13, 0,14, 9, |
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154 | 14,11, 2,12, 4, 7,13, 1, 5, 0,15,10, 3, 9, 8, 6, |
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155 | 4, 2, 1,11,10,13, 7, 8,15, 9,12, 5, 6, 3, 0,14, |
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156 | 11, 8,12, 7, 1,14, 2,13, 6,15, 0, 9,10, 4, 5, 3 |
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157 | }, |
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158 | |
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159 | { |
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160 | 12, 1,10,15, 9, 2, 6, 8, 0,13, 3, 4,14, 7, 5,11, |
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161 | 10,15, 4, 2, 7,12, 9, 5, 6, 1,13,14, 0,11, 3, 8, |
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162 | 9,14,15, 5, 2, 8,12, 3, 7, 0, 4,10, 1,13,11, 6, |
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163 | 4, 3, 2,12, 9, 5,15,10,11,14, 1, 7, 6, 0, 8,13 |
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164 | }, |
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165 | |
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166 | { |
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167 | 4,11, 2,14,15, 0, 8,13, 3,12, 9, 7, 5,10, 6, 1, |
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168 | 13, 0,11, 7, 4, 9, 1,10,14, 3, 5,12, 2,15, 8, 6, |
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169 | 1, 4,11,13,12, 3, 7,14,10,15, 6, 8, 0, 5, 9, 2, |
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170 | 6,11,13, 8, 1, 4,10, 7, 9, 5, 0,15,14, 2, 3,12 |
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171 | }, |
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172 | |
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173 | { |
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174 | 13, 2, 8, 4, 6,15,11, 1,10, 9, 3,14, 5, 0,12, 7, |
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175 | 1,15,13, 8,10, 3, 7, 4,12, 5, 6,11, 0,14, 9, 2, |
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176 | 7,11, 4, 1, 9,12,14, 2, 0, 6,10,13,15, 3, 5, 8, |
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177 | 2, 1,14, 7, 4,10, 8,13,15,12, 9, 0, 3, 5, 6,11 |
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178 | } |
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179 | }; |
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180 | |
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181 | /* P is a permutation on the selected combination of the current L and key. */ |
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182 | static const char P[] = { |
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183 | 15, 6,19,20, 28,11,27,16, 0,14,22,25, 4,17,30, 9, |
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184 | 1, 7,23,13, 31,26, 2, 8, 18,12,29, 5, 21,10, 3,24 |
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185 | }; |
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186 | |
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187 | /* The current block, divided into 2 halves. */ |
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188 | static char L[64]; |
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189 | #define R (L+32) |
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190 | static char tempL[32]; |
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191 | static char f[32]; |
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192 | |
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193 | /* The combination of the key and the input, before selection. */ |
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194 | static char preS[48]; |
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195 | |
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196 | /* The payoff: encrypt a block. */ |
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197 | void encrypt(char block[64],int edflag) |
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198 | { |
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199 | int i, ii; |
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200 | register int t, j, k; |
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201 | |
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202 | (void)edflag; |
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203 | /* First, permute the bits in the input */ |
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204 | for(j=0; j < 64; j++) |
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205 | L[j] = block[(int)IP[j]]; |
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206 | /* Perform an encryption operation 16 times. */ |
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207 | for(ii=0; ii < 16; ii++) { |
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208 | i = ii; |
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209 | /* Save the R array, which will be the new L. */ |
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210 | for(j=0; j < 32; j++) |
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211 | tempL[j] = R[j]; |
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212 | /* Expand R to 48 bits using the E selector; |
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213 | * exclusive-or with the current key bits. |
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214 | */ |
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215 | for(j=0; j < 48; j++) |
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216 | preS[j] = R[E[j]-1] ^ KS[i][j]; |
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217 | /* The pre-select bits are now considered in 8 groups of 6 bits each. |
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218 | * The 8 selection functions map these 6-bit quantities into 4-bit |
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219 | * quantities and the results permuted to make an f(R, K). |
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220 | * The indexing into the selection functions is peculiar; |
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221 | * it could be simplified by rewriting the tables. |
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222 | */ |
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223 | for(j=0; j < 8; j++) { |
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224 | t = ((j<<1)+j)<<1; |
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225 | k = S[j][(preS[t]<<5)+ |
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226 | (preS[t+1]<<3)+ |
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227 | (preS[t+2]<<2)+ |
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228 | (preS[t+3]<<1)+ |
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229 | (preS[t+4] )+ |
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230 | (preS[t+5]<<4)]; |
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231 | t = j << 2; |
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232 | f[t ] = (k>>3)&01; |
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233 | f[t+1] = (k>>2)&01; |
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234 | f[t+2] = (k>>1)&01; |
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235 | f[t+3] = (k )&01; |
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236 | } |
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237 | /* The new R is L ^ f(R, K). The f here has to be permuted first, though. */ |
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238 | for(j=0; j < 32; j++) |
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239 | R[j] = L[j] ^ f[(int)P[j]]; |
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240 | /* Finally, the new L (the original R) is copied back. */ |
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241 | for(j=0; j < 32; j++) |
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242 | L[j] = tempL[j]; |
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243 | } |
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244 | /* The output L and R are reversed. */ |
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245 | for(j=0; j < 32; j++) { |
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246 | L[j] ^= R[j]; |
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247 | R[j] ^= L[j]; |
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248 | L[j] ^= R[j]; |
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249 | } |
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250 | /* The final output gets the inverse permutation of the very original. */ |
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251 | for(j=0; j < 64; j++) |
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252 | block[j] = L[(int)FP[j]]; |
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253 | } |
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254 | |
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255 | char * crypt(const char *pw, const char *salt) |
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256 | { |
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257 | register int i, j, c; |
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258 | static char block[66], iobuf[16]; |
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259 | #ifdef WANT_CRYPT_MD5 |
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260 | if (salt[0]=='$' && salt[1]=='1' && salt[2]=='$') |
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261 | return md5crypt(pw,salt); |
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262 | #endif |
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263 | for(i=0; i < 66; i++) |
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264 | block[i] = 0; |
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265 | for(i=0; (c= *pw) && i < 64; pw++) { |
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266 | for(j=0; j < 7; j++, i++) |
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267 | block[i] = (c>>(6-j)) & 01; |
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268 | i++; |
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269 | } |
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270 | |
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271 | setkey(block); |
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272 | |
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273 | for(i=0; i < 66; i++) |
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274 | block[i] = 0; |
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275 | |
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276 | for(i=0; i < 2; i++) { |
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277 | c = *salt++; |
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278 | iobuf[i] = c; |
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279 | if(c > 'Z') |
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280 | c -= 6; |
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281 | if(c > '9') |
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282 | c -= 7; |
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283 | c -= '.'; |
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284 | for(j=0; j < 6; j++) { |
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285 | if((c>>j) & 01) { |
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286 | int ind1 = (((i<<1)+i)<< 1) + j; |
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287 | int ind2 = ind1 + 24; |
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288 | E[ind1] ^= E[ind2]; |
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289 | E[ind2] ^= E[ind1]; |
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290 | E[ind1] ^= E[ind2]; |
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291 | } |
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292 | } |
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293 | } |
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294 | |
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295 | for(i=0; i < 25; i++) |
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296 | encrypt(block,0); |
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297 | |
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298 | for(i=0; i < 11; i++) { |
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299 | c = 0; |
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300 | for(j=0; j < 6; j++) { |
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301 | c <<= 1; |
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302 | c |= block[(((i<<1)+i)<<1)+j]; |
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303 | } |
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304 | c += '.'; |
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305 | if(c > '9') |
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306 | c += 7; |
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307 | if(c > 'Z') |
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308 | c += 6; |
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309 | iobuf[i+2] = c; |
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310 | } |
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311 | iobuf[i+2] = 0; |
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312 | if(iobuf[1] == 0) |
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313 | iobuf[1] = iobuf[0]; |
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314 | return(iobuf); |
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315 | } |
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